Question

Find the value of q so that equation 2xsquare-3px+5q=0 has one root which is twice the other

Answer 1

Answer:q= 5

Step-by-step explanation: hope u get it ! All the best ✌

Answer 2

The value of q becomes $\dfrac{p^2}{5}$

Step-by-step explanation:

Since we have given that

$2x^2-3px+5q=0$

Let a be the first root and b be the second root.

Since one root which is twice the other,

So, b = 2a

Sum of zeroes  is given by

$a+2a=\dfrac{3p}{2}\\\\3a=\dfrac{3p}{2}\\\\a=\dfrac{p}{2}$

Product of zeroes is given by

$a\times 2a=\dfrac{5q}{2}\\\\2a^2=\dfrac{5q}{2}\\\\a^2=\dfrac{5q}{4}$

Now, put the value of a in the above equation,

$(\dfrac{p}{2})^2=\dfrac{5q}{4}\\\\\dfrac{p^2}{4}=\dfrac{5q}{4}\\\\\dfrac{p^2}{5}=q$

Hence, the value of q becomes $\dfrac{p^2}{5}$

# learn more:

Find the value of q so that equation 2xsquare-3px+5q=0 has one root which is twice the other

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