Question

find the value of q so that the equation 2 x square - 3p x + 5q is equals to zero has one root which is twice the other​

Answer 1

Answer:

answer is attached

hope it helps you

Answer 2

Answer:

Step-by-step explanation: Given quadratic equation is

$2x^{2} -3px+5q=0$

Let the one root be k, then the 2nd root will be 2k.

Now, Sum of the roots = k + 2k = $\frac{3p}{2}$

3k = $\frac{3p}{2}$

k = p/2

And the product of the roots = k(2k) = $\frac{5q}{2}$

$2k^{2} =\frac{5q}{2}$

$2(\frac{p}{2}) ^{2} =\frac{5q}{2}$

$q=\frac{p^{2} }{5}$