Find the value of q(t)=4t³-3t2-5t-4 at t= -2 2
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Step-by-step explanation:
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Given, q(t)=4t³-3t²-5t-4
and, t=(-22)
Putting the value of 't',
q(-22)=4×(-22)³ - 3×(-22)² - 5×(-22) - 4
q(-22)=4×(-10648) - 3×(484) -5×-22 - 4
q(-22)=(-42592)-(1452)+(110)-(4)
q(-22)=(-42592-1452+110-4)
q(-22)= '-43938'
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Hence, the value of polynomial q(t)=(-43938)
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