Question

Find the value of r......

Answer 1

Answer:

$\frac{2}{ {r}^{2} } = \frac{1}{ {(x - r)}^{2} } \\ \\ 2 {(x - r)}^{2} = {r}^{2} \\ \\with \: positive \: sign. = > \\ \\ x - r = \frac{r}{ \sqrt{2} } \\ \\ x = r( \frac{ \sqrt{2} + 1 }{ \sqrt{2} } ) \\ \\ r = x( \frac{ \sqrt{2} }{ \sqrt{2} + 1} ) \\ \\ with \: negative \: sign. = > \\ \\ x - r = - \frac{r}{ \sqrt{2} } \\ \\ x = r( \frac{ \sqrt{2} - 1 }{ \sqrt{2} } ) \\ \\ r = x( \frac{ \sqrt{2} }{ \sqrt{2 } - 1} )$

Answer 2

Answer:

hope it helps

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