Question

Find the value of 'R', whose roots of quadratic equation (R-4)x^2 + 2(R-4)x+2=0.​

Answer 1

Step-by-step explanation:

hope this answer will be helpful

Answer 2

the value of R = 4 and 6

we have to find the value of ‘R’, whose roots of quadratic equation (R-4)x^2 + 2(R-4)x+2=0 have equal.

discriminant, D = b² - 4ac = 0

⇒{2(R - 4)}² - 4 × 2 × (R - 4) = 0

⇒4(R - 4)² - 8(R - 4) = 0

⇒4(R - 4){(R - 4) - 2} = 0

⇒4(R - 4)(R - 6) = 0

⇒R = 4, 6

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