Find the value of root 32 plus root 48 by root 8 plus root 12
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root 32=4root2
root48=4root3
root8=2root2
root12=2root3
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root48=4root3
root8=2root2
root12=2root3
ATQ
answer in photo
HOPE IT HELP U
ADD IT AS BRANLIST plz
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(root 32 +root 48)/(root 8 +root 12) [root 32 = 4 root 2]
[root 48 = 4 root 3]
[root 8 = 2 root 2]
[root 12 = 2 root 3]
so it is
(4 root 2+ 4 root 3)/(2 root 2 + 2 root)
take 4 as common in numerator
and 2 as common in denominator
then
(4*(root 2 + root 3))/(2*(root 2 + root 3))
(root 2 + root 3) will get cancelled then
it will be
(4)/(2)
SO
THE FINAL ANSWER IS "2"
[root 48 = 4 root 3]
[root 8 = 2 root 2]
[root 12 = 2 root 3]
so it is
(4 root 2+ 4 root 3)/(2 root 2 + 2 root)
take 4 as common in numerator
and 2 as common in denominator
then
(4*(root 2 + root 3))/(2*(root 2 + root 3))
(root 2 + root 3) will get cancelled then
it will be
(4)/(2)
SO
THE FINAL ANSWER IS "2"
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