Math, asked by momdad143, 11 months ago

FIND THE VALUE OF ROOT10 -ROOT5 /2 ROOT2

Answers

Answered by haridasan85
0

V10-v5/2v2 = 3.16 -2.24/2x1.4l

= 0. 92/2.82=92/282

= 0.33 is the ans.

Answered by AnuragMishra14
0

 \frac{ \sqrt{10} -  \sqrt{5}  }{2 \sqrt{2} }

  \frac{ \sqrt{10}  -  \sqrt{5} }{ \sqrt{8} }

Rationalising the denominator

( \frac{ \sqrt{10}  -  \sqrt{5} }{ \sqrt{8} } ) \times  \frac{ \sqrt{8} }{ \sqrt{8} }

 \frac{ \sqrt{80}  -  \sqrt{40} }{8}

 \frac{4 \sqrt{5}  - 2 \sqrt{10} }{8}

 \frac{2 \sqrt{5 } -  \sqrt{10}  }{4}

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