Question

find the value of sec (13π|3)​

Answer 1

Solution :

$\sf \bf \: = sec \bf\frac{13\pi}{3} = sec(4\pi + \bf\frac{\pi}{3} )$

$\sf \: \: \: \: = sec \: \sf\frac{\pi}{3} \: since \: 4\pi \: + θ \: is \: in \: first \: quadrant$

$\sf \: \: \: \: \: \: \: = sec(4\pi + θ) \: is \: positive$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf= 2$

⭐ Hope you understand this answer mate ⭐

Answer 2

Question :-

Find the value of :-

$\sf \sec( \frac{13\pi}{3} )$

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Solution :-

$\bf {\underline { \pink{given : - }}} \begin{cases} \sec( \frac{13\pi}{3} ) \: \end{cases}$

$\bf \underline{ \green {to \: find : - }} \begin{cases} \sf{value \: of} \to \sec( \frac{13\pi}{3} ) \end{cases}$

$\bf \: \underline{ \red{calculation}} \downarrow$

$</p><p>\sf\: = sec \sf\frac{13\pi}{3} = sec(4\pi + \sf\frac{\pi}{3} )</p><p>\\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = sec \: \sf\frac{\pi}{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \small \blue{( \because \: 4\pi \: + θ \: is \: in \: first \: quadrant)}</p><p> \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: = sec(4\pi + θ) \: is \: positive</p><p>\: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf= \red 2</p><p>$

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Final Answer :-

The answer to sec(13π/3) is 2.

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Note:-

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