Question

find the value of sec 15 degrees by cosec 75 degrees + sin 72 degrees by cos 18 degrees minus Tan 33 degrees by cot 57 degrees​

Answer 1

Answer:

• by the given;that, sec15/cosec75+sin72/cos18-tan33/cot57. sec(90-75)/cosec75+sin(90-18)/cos18-tan(90-57)/cot57

• cosec75/cosec75+cos18/cos18-cot57/cot57
• 1+1-1
• 2-1
• 1

therefore the value is 1

Answer 2

Answer:

2

Step-by-step explanation:

sec15/cosec75+sin 72/cos18×tan33/cot 57

codec(90-15)/cosec75+sin(90-72)/cos18×tan(90-33)/cot57

cosec75/cosec75+sin18/sin18×tan57/tan57

1+1×1

2×1

2