Question

find the value of sec(150°)
with step- by- step explanation

11th grade ch: Trigonometric Functions
(no absurd answers pls(〒﹏〒)​)​

Answer 1

Answer:

Trigonometrical ratios of some particular angles i.e., 120°, -135°, 150° and 180° are given below.

1. sin 120° = sin (1 × 90° + 30°) = cos 30° = √32;

cos 120° = cos (1 × 90° + 30°) = - sin 30° = - 12;

tan 120° = tan (1 × 90° + 30°) = - cot 30° = - √3;

csc 120° = csc (1 × 90° + 30°) = sec 30° = 2√3;

sec 120° = sec (1 × 90° + 30°) = - csc 30° = - 2;

tan 120° = tan (1 × 90° + 30°) = - cot 30° = - √3;

cot 120° = cot (1 × 90° + 30°) = - tan 30° = - 1√3.

Answer 2

Answer:

Find the value of sec(150°) with step- by- step explanation 11th grade ch: Trigonometric Functions (no absurd answers ...