find the value of sec(150°)
with step- by- step explanation
11th grade ch: Trigonometric Functions
(no absurd answers pls(〒﹏〒))
Answers
Answered by
0
Answer:
Trigonometrical ratios of some particular angles i.e., 120°, -135°, 150° and 180° are given below.
1. sin 120° = sin (1 × 90° + 30°) = cos 30° = √32;
cos 120° = cos (1 × 90° + 30°) = - sin 30° = - 12;
tan 120° = tan (1 × 90° + 30°) = - cot 30° = - √3;
csc 120° = csc (1 × 90° + 30°) = sec 30° = 2√3;
sec 120° = sec (1 × 90° + 30°) = - csc 30° = - 2;
tan 120° = tan (1 × 90° + 30°) = - cot 30° = - √3;
cot 120° = cot (1 × 90° + 30°) = - tan 30° = - 1√3.
Answered by
44
Answer:
Find the value of sec(150°) with step- by- step explanation 11th grade ch: Trigonometric Functions (no absurd answers ...
Similar questions