find the value of sec 45 , cosec30 and cos60 geometrically.
pls fast its urgent
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Answer:
cos (theta) is the ratio of base and hypotenuse in a right angled triangle say ∆ABC
Since in the right angled triangle one angle is 45° so other one will be 45° too. If length of base is a unit hence the length of perpendicular. so length of hypotenuse = a√2
so cos45°= a/a√2 =1/√2
sec45°= √2
Next incase of theta=30°
take an equilateral triangle say ∆PQR with each side of length a unit.
now draw a perpendicular from vertex Q to base PR to meet at M. so length of PM=MR=a/2 so length of QM = a√3/2
in this figure u can find ratio of sides similar to above for theta=30° or 60°
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