Question

find the value of sec 45 geometrically ​

Answer 1

Answer:

Let us take a right angle triangle ABC

Angle B= 90°

Let BC be a and AB be a

(AC) ^2 =( AB) ^2 + (BC) ^2

So, Ac = root a^2 + a ^2

Ac = root 2 a

Let the teta at angle c

So, Sec C = hypo/ adj.

Sec C = Ac /Bc

Sec C = root 2 a / a

a will get cancelled and we get root 2 as our answer