Math, asked by sejalsalekar8, 6 months ago

find the value of sec -855°​

Answers

Answered by babalpreetkaur
19

Step-by-step explanation:

sec (-855°)

=sec (-1080°+135°)

=sec(135°)

=sec (90°+45°)

= -cosec45°

 =  -  \sqrt{2}

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Answered by ritikkumar269
0

Answer:

The value of sec -855°​ is  -\sqrt{2}.

Step-by-step explanation:

The sec of any angle in a right triangle is the ratio of the length of the adjacent side to the length of the hypotenuse.

We are asked to find the value of \sec -855^{\circ}:

Calculate the required value using the trigonometric properties as shown below:

\sec(-855^{\circ})\\=\sec \left(-1080^{\circ}+135^{\circ}\right)$$

\begin{aligned}&=\sec \left(135^{\circ}\right) \\&=\sec \left(90^{\circ}+45^{\circ}\right)\end{aligned}

&=-cosec 45^{\circ} \\&=-\sqrt{2}

Therefore, the value of sec -855^{\circ} is -\sqrt{2} .

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