find the value of sec A,if sin A=3/5.
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Answered by
2
Sin A = 3/5
Therefore cos A = 4/5
Hence sec A = 5/4
Hope this helps you...:)
Therefore cos A = 4/5
Hence sec A = 5/4
Hope this helps you...:)
Answered by
2
sin A = 3/5
sin^2 A = 9/25
cos^2 A = 1 - sin^2 A
= 1-9/25
=16/25
cos A = +- 4/5
sec A = 1/ cosA = +- 5/4
[since the coordinates' not mentioned signs cannot be decided]
sin^2 A = 9/25
cos^2 A = 1 - sin^2 A
= 1-9/25
=16/25
cos A = +- 4/5
sec A = 1/ cosA = +- 5/4
[since the coordinates' not mentioned signs cannot be decided]
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