find the value of sec theta if sin theta is equal to 3 upon 5
Answers
Answered by
22
as we know that
sin^2 A + cos^2 A = 1
( 3/5 )^2 + cos^2 A = 1
cos^2 A = 1 - 9/25
cos^2 A = 16/25.
cos A = 4/5
sec A = 1/cos A
= 1/4/5
= 5/4
so sec A = 5/4
sin^2 A + cos^2 A = 1
( 3/5 )^2 + cos^2 A = 1
cos^2 A = 1 - 9/25
cos^2 A = 16/25.
cos A = 4/5
sec A = 1/cos A
= 1/4/5
= 5/4
so sec A = 5/4
Answered by
11
given that , sin t = 3/5
we know ,
sin^2 t + cos^2 t = 1
then ,
(3/5)^2 + cos^2 t = 1
cos^2 t = 1 - 9/25
cos^2 t = 16/25
cos t = 4/5
so , sec t =5/4
we know ,
sin^2 t + cos^2 t = 1
then ,
(3/5)^2 + cos^2 t = 1
cos^2 t = 1 - 9/25
cos^2 t = 16/25
cos t = 4/5
so , sec t =5/4
sksingh7:
thanks
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