Question

find the value of sec x cosec x = - 2/√3 where x lies in |||rd quadrant​

Answer 1

Answer:

Step-by-step explanation:

$sec x cosec x = - 2/\sqrt{3}$

$\frac{1}{sinxcosx} = -2/\sqrt{3}$                    -----------(1)

$we\ know\ that$,

$sin^{2} x+cos^{2} x+2sinxcosx=(sinx+cosx)^{2}$

$\frac{sin^{2} x+cos^{2} x-(sinx+cosx)^{2}}{2} =sinxcosx$

$put\ in\ equation\ (1)$

$\frac{1-(sinx+cosx)^{2}}{2} =\frac{-\sqrt{3} }{2}$

$(sinx+cosx)^{2}}=1+{\sqrt{3} }$