Question

find the value of sec0°×tan0°​

Answer 1

Answer:

Step-by-step explanation:

sec0+ tan 0 = x

                           … (Given )(equation1 )

Since ,

sec²0 - tan²0 = 1

( sec0 - tan0 ) ( sec0 + tan0 ) = 1

( sec0 - tan 0 ) (x) = 1

sec0 - tan0 = 1/ x

Therefore value of sec0 - tan 0 is 1/x

Answer 2

Answer:

0

Step-by-step explanation:

sec0°= 1

tan0°= 0

therefore sec0°×tan0°= 1×0 = 0