Question

Find the value of sec2 53° - 1/cot² 53°​

Answer 1

Answer:

tan 12° cot 38° cot(90° – 38°) cot 60° tan(90° – 12°) = tan 12° cot 38° tan 38° cot 60° cot 12° [∵ cot(90° – θ) = tan θ] = tan12° x 1/tan12° x cot38° x 1/cot38° x cot60°

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Answer 2

Answer:

The answer is 1

Step-by-step explanation:

$sec^{2} (53) - \frac{1}{ \cot^{2} (53) } \\ \ = { \sec(53) }^{2} - { \tan(53) }^{2} \\ = 1$