Question

Find the value of simple interest, time (P-1500,R-10%,T-?,SI-?,A-1950

Answer 1

3 yr

Step-by-step explanation:

${\underline{{\text{Given}}}}$

Principal(P) = ₹ 1500

Rate of interest (r) = 10%

Amount(A) = ₹ 1950

${\underline{{\text{To Find:}}}}$

Time(t)

Simple Interest(S.I)

_______________________________________

Using Amount Formula,

$\text{P} =A × \dfrac{100}{100+rt}$

Where,

P = Principal

r = rate of interest

t = time

S.I = Simple Interest

A = Amount

${\underline{{\text{Solution:}}}}$

$\text{P} =A × \frac{100}{(100+rt)} \\ \\ 1500 = 1950 \times \frac{100}{100 + 10 \times t} \\ \\ \frac{1500}{100} = \frac{1950}{100 + 10t} \\ \\ \cancel{15} = \frac{ \cancel{1950} }{100 + 10t} \\ \\ (100 + 10t) = 130 \\ \\ 10t = 130 - 10 0\\ \\ 10t = 30 \\ \\ t = 3$

Hence, The required time is 3 yr and Simple Interest is ₹ (1950 - 1500) = ₹ 450

Answer 2

Solution:

Given:

Principal(P)=1500

Rate(R)=10%

Time(T)=?

Simple Interest(S.I)=?

Amount(A)=1950

Now,

Simple interest(S.I)=Amount-Simple Interest

                              =1950-1500

                              =450

again,

using time formula

Time(T)=(S.I*100)/P*R

            =(450*100)/1500*10

            =45000/15000

           =3 years

therefore, the time is 3 years and simple interest is 450.