Find the value of sin 0° sin 30° - cos 90° cos 30°
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sin(90+30) is in the form of sin (A+B)
sin(A+B)= sinA cosB+CosA sinB
sin(90+30)=sin90 cos30 + cos90 sin30
sin90°=1,cos90°=0,sin30°=1/2 and cos30°= √3/2
sin(90+30)= 1×√3/2+0
sin(90+30)= √3/2
cos (30) =√3/2
sin(90+30)=cos(30)
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