Question

find the value of= sin^-1 sin(-610°)​

Answer 1

Answer:

Its value is 70.

Step-by-step explanation:

Given:

$sin^{-1}sin(610\°)$

Firstly we are evaluating the value of $sin(610\°)$.

$sin(610\°)\\= sin(360\°+250\°)\\= sin(2\pi+250\°)\\= sin(250\°)\\sin(250\°)\\= sin(\pi +70\°)\\=sin(70\°)$

Now substituting the value of