find the value of sin 120 cos 330-sin 240cos 390
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Answer:
3/2
Step-by-step explanation:
=sin 120 cos 330 -sin 240 cos 390
=sin (90×1 +30) cos (90×3 +60) - sin(90×2 +60) cos (90×4+ 30)
= cos 30 sin60 + sin60 cos 30
= √3/2 × √3/2 + √3/2 × √3/2
= 3/4+3/4
=6/4
=3/2
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