Math, asked by sourabhsarfale3713, 9 months ago

find the value of sin 15°​

Answers

Answered by Sringjona
12

Answer:

sin 15° = (√3−1)/2√2

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Answered by AdarshAbrahamGeorge
9

Answer:

sin15° = (√3-1) / (2√2)

= 0.2588190451

Step-by-step explanation:

Sin15° = sin(45° - 30°)

= sin 45°. Cos30° - cos45°. sin30° ( trigonometric function of difference of angles)

=( 1/√2)*(√3/2) - (1/√2)*(1/2)

= √3/(2√2) - 1/(2√2)

= (√3-1) / (2√2)

= sin15° = (√3-1) / (2√2)

= 0.2588190451

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