Math, asked by sanyasikaranam78, 4 months ago

Find the value of sin^2 2π/3+cos^2 5π/6-tan^2 3π/4​

Answers

Answered by amazingkurl
2

Answer:

1/2

Step-by-step explanation:

sin^2 (2π/3)+cos^2 (5π/6)-tan^2 (3π/4)

=sin^60+cos^30-tan^45

= 3/4 +3/4 -1

=1/2

Answered by keyarozario3
2

Answer:

1/2

Step-by-step explanation:

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