find the value of sin^2 20°+sin^2 70°-tan^2 45°
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Given, sin^2 20°+sin^2 70°-tan^2 45°
= sin^2 20°+sin^2(90° - 20°) - tan^2 45°
= sin^2 20°+cos^2 20°-1
= 1 - 1
= 0 (Ans.)
AvneetKaurSandhu:
tnxx alots...☺
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