Question

find the value of sin^2 30°+ cos^2 30°+ cot^2 45°​

Answer 1

➭ Answer :-

sin²30°+ cos²30°+ cot²45° = 2

➭ To find :-

• sin²30°+ cos²30°+ cot²45°

➭ Solution :-

we know,

$\longrightarrow \sf \sin {30}^{0} = \frac{1}{2}$

$\longrightarrow \sf cos {30}^{0} = \frac{ \sqrt{3} }{2}$

$\longrightarrow \sf cot {45}^{0} = 1$

so,

$\longrightarrow \sf \bigg( \frac{1}{2} \bigg) ^{2} + \bigg( \frac{ \sqrt{3} }{2} \bigg)^{2} +(1)^{2}$

$\longrightarrow \sf \frac{1}{4} + \frac{3}{4} + 1$

$\longrightarrow \sf \frac{1 + 3 + 4}{4}$

$\longrightarrow \sf \cancel \frac{8}{4} = 2$

Hence,sin²30°+ cos²30°+ cot²45° = 2