Math, asked by rockstar619, 3 months ago


Find the value of sin^2 30°+cos^2 60°+tan^2 45º​

Answers

Answered by bagkakali
1

Answer:

sin^2 30°+cos^2 60°+tan^2 45°

=(1/2)^2+(1/2)^2+(1)^2

=1/4+1/4+1

=1/4+1/4+4/4

=(1+1+4)/4

=6/4

=3/2

=1 1/2

Answered by Anonymous
0

Answer:

 \sin {}^{2} 30 {}^{0}  +  \cos {}^{2} 60 {}^{0}   +  \tan {}^{2} \: 45 {}^{0}

( \frac{1}{2} ) {}^{2}  + ( \frac{1}{2} ) {}^{2}  + (1)

 \frac{1}{4}  +  \frac{1}{4}  + 1

 \frac{1}{4} +  \frac{1}{4}  +  \frac{4}{4}

 \frac{(1 + 1 + 4}{4}

 \frac{6}{4}

 \frac{3}{2}

 \frac{11}{2}

I hope answer is helpful to us

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