Question

Find the value of sin^2 54 + sin^2 36​

Answer 1

Answer:

HII! HERE'S YOUR ANSWER

=cos²36-sin²54

=cos²36-sin²(90-36)

=cos²36-cos²36

=(cos236-cos236) get canceled

=1-1

=0

so, the answer is 0

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Step-by-step explanation:

Answer 2

Answer:

Required value of sin^2 54 + sin^2 36 is 1.

Step-by-step explanation:

Given,

${sin}^{2} 54 + {sin}^{2} 36$

We know,

$\sin(90 - \theta) = \cos( \theta)$

So,

$\sin(36) = \sin(90 - 54) = \cos( 54)$

So,

${sin}^{2} 54 + {sin}^{2} 36 \\ = {sin}^{2} 54 + { \cos }^{2} 54 \\ = 1$

Here applied formula,

${sin}^{2} \theta \: + {cos}^{2} \theta \: = 1$

Some important Trigonometry formula,

$sin(x) = \cos(\frac{\pi}{2} - x) \\ \tan(x) = \cot(\frac{\pi}{2} - x) \\ \sec(x) = \csc(\frac{\pi}{2} - x) \\ \cos(x) = \sin(\frac{\pi}{2} - x) \\ \cot(x) = \tan(\frac{\pi}{2} - x) \\ \csc(x) = \sec(\frac{\pi}{2} - x)$

know more about Trigonometry,

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