Question

find the value of sin^2 54+ sin^2 36​

Answer 1

$\large\color{#3fff00}\boxed{\colorbox{000080}{Answer : - }}$

$sin ^{2} 54 + \sin ^{2} 36$

$= sin ^{2} 54 + {sin}^{2} (90 - 54)$

$= \sin^{2} \: 54 + {cos}^{2} \: 54$

$\color{red}[cos^2θ + sin^2 \theta = 1]$

$= 1$