Find the value of sin 2 awhen tan a =
2/7
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Answer:
Sin theta is given by = Perpendicular/
Hypotenuse
And, Tan theta = Perpendicular / Base = 2/7
{given}
Thus solving it with Pythagoras theorem we get ;
(Hypotenuse)^2 = (Perpendicular)^2 +
(Base)^2
AB^2 = [ (2)^2 + (7)^2 ] = √53 units
Sin 2A = 2/√53
Hope it helps : )
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