find the value of (sin^2 theta)/(cos theta) + cos theta = 1/(cos theta)
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Firstly take L.H.S.(left hand side),
i.e.
L
H
S
=1−(sin2θ1−cosθ)=1−[1−cos21−cosθ]
=1−[12−(cosθ)21−cosθ]=1−(1+cosθ)(1−cosθ)(1−cosθ)
so after solving it will give,
=1−(1+cosθ)=1−1−cosθ
which will give,
= − cos θ= RHS
hence proved.
hope this helps you
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