Question

find the value of sin 25pi/3 using trigonometric function

Answer 1

Answer:

hey mate your answer is here......

➡25π/3

➡25×180/3

➡25×60

➡ 1500

➡sin (4π+π/3)

➡sinπ/3

➡√3/2

hope this will help you buddy ❤❤

Answer 2

The value of   $\sin \dfrac{25\pi}{3}$   is   $\dfrac{\sqrt{3} }{2}$

Step-by-step explanation:

To find the value of  $\sin \dfrac{25\pi}{3}$

according to question we have

$\sin \dfrac{25\pi}{3}$  

which can also be written as

$\sin(8 \pi + \dfrac{\pi}{3})$

Now $sin (n\pi +\theta ) = \sin \theta$ and $(8 \pi + \dfrac{\pi}{3})$ lies in first quadrant

therefore

$\sin(8 \pi + \dfrac{\pi}{3}) = \sin \dfrac{\pi}{3} = \dfrac{\sqrt{3} }{2}$

Hence, the value of   $\sin \dfrac{25\pi}{3}$   is   $\dfrac{\sqrt{3} }{2}$

#Learn more

Cos 10π/13 + Cos 8π/13 + Cos 3π/13 + Cos 5π/13 = 0 ......Prove it

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