Question

find the value of sin 28 degree ÷ cos 62 degree​

Answer 1

We must recall the relationship between trigonometric ratios

$\cos(90-\theta)=\sin\theta$

Given: $\frac{\sin 28^\circ}{\cos 62^\circ}$

We can write the denominator as

$\cos 62^\circ=\cos(90^\circ-28^\circ)$

We know,  $\cos(90-\theta)=\sin\theta$

$\implies\cos62^\circ=\sin28^\circ$

So the value is

$\implies\frac{\sin 28^\circ}{\cos 62^\circ}=\frac{\sin 28^\circ}{\sin 28^\circ}\\\\\implies1$

Hence the value of $\frac{\sin 28^\circ}{\cos 62^\circ}=1$

Answer 2

$\displaystyle \sf{ \frac{cos \: {28}^{ \circ} }{sin\: {62}^{ \circ}} } = \bf 1$

Given :

The expression

$\displaystyle \sf{ \frac{cos \: {28}^{ \circ} }{sin\: {62}^{ \circ}} }$

To find :

The value of the expression

Formula :

sin( 90° - θ ) = cos θ

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

$\displaystyle \sf{ \frac{cos \: {28}^{ \circ} }{sin\: {62}^{ \circ}} }$

Step 2 of 2 :

Find the value of the expression

We use the formula

sin( 90° - θ ) = cos θ

Thus we get

$\displaystyle \sf{ \frac{cos \: {28}^{ \circ} }{sin\: {62}^{ \circ}} }$

$\displaystyle \sf{ = \frac{cos \: {28}^{ \circ} }{sin\: ({90}^{ \circ} - {28}^{ \circ} )} }$

$\displaystyle \sf{ = \frac{cos \: {28}^{ \circ} }{cos \: {28}^{ \circ} } }$

$= 1$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ If cosθ+secθ=√2,find the value of cos²θ+sec²θ

https://brainly.in/question/25478419

2. Value of 3 + cot 80 cot 20/cot80+cot20 is equal to

https://brainly.in/question/17024513