Math, asked by gamerzzone5172008, 19 days ago

Find the value of sin 2A, cos 2A and tan 2A if tan A =4/3

Answers

Answered by samitbanerjee25
0

Answer:

24/25 , - 7/25 , - 24/7

Step-by-step explanation:

sin 2A = 2tan A/(1 + tan²A) = (2 . 4/3)/[(1 + (4/3)²] = 24/25

cos 2A = (1 - tan²A)/(1 + tan²A) = [1 - (4/3)²]/[1 + (4/3)²] = - 7/25

tan 2A = 2tan A/(1 - tan²A) = (2 . 4/3)/[1 - (4/3)²] = - 24/7

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