Question

find the value of sin 2A when, 1)cosA=3/5 2)sinA=12/13 3) tanA=16/63​

Answer 1

Step-by-step explanation:

Sin2a = 2sinAcosA

tan a= sina/cosa

or tan a= p/b = 16/63

so we get p =16 b= 63

we need to find the third side h so we use pythagorous theorem

c= √p^2+b^2

c= √16^2+63 ^2= √4225 = 65

so we got hypotaneious side dude

now

sin a = p/h which means

sin a = 16/65

and cos a= b/h which means

cos a = 63/65

now we need to calculate sin2a

sin2 a = 2sin a cos a

now we can directly put our values

sin2 a = 2x16/65 x63/65 = 0.47 approx dude have any doubt ask in comment box

sin 2 a = 0.47