Math, asked by sumanth2201, 9 months ago

FIND THE VALUE OF SIN 2A WHEN COS A = 3/5

Answers

Answered by vishalkumarv2020
2

Answer:

24/25

Step-by-step explanation:

first we convert cos A into sin A.

so, sin A=4/5

since, cos A= 3/5 that means, base of triangle is 3 and hypothesis is 5. therefore, perpendicular is 4.

sinA =perpendicular/hypothesis

so sin A=4/5.

sin2A= 2×sinA×cosA

sin2A= 2×4/5×3/5

sin2A= 24/25

Answered by rajeev3989
0

Step-by-step explanation:

Cos A =b/h

B=3 H=5

By phythagoras theoram ,

H^2=B^2+P^2

=》5^2=3^2+P^2

=》25=9+P^2

=》P^2=25-9

=》P^2=16

=》P=4

Sin 2A=2SinA×CosA

=》2×4/5×3/5

=》24/25

Hope you will like this .... :-)

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