FIND THE VALUE OF SIN 2A WHEN COS A = 3/5
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Answered by
2
Answer:
24/25
Step-by-step explanation:
first we convert cos A into sin A.
so, sin A=4/5
since, cos A= 3/5 that means, base of triangle is 3 and hypothesis is 5. therefore, perpendicular is 4.
sinA =perpendicular/hypothesis
so sin A=4/5.
sin2A= 2×sinA×cosA
sin2A= 2×4/5×3/5
sin2A= 24/25
Answered by
0
Step-by-step explanation:
Cos A =b/h
B=3 H=5
By phythagoras theoram ,
H^2=B^2+P^2
=》5^2=3^2+P^2
=》25=9+P^2
=》P^2=25-9
=》P^2=16
=》P=4
Sin 2A=2SinA×CosA
=》2×4/5×3/5
=》24/25
Hope you will like this .... :-)
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