FIND THE VALUE OF SIN 2A WHEN COS A = 3/5
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Answer:
sin2A=2sinAcosA
cos A=3/5
using pythagoras theorem
sinA=4/5
sin2A=2sinAcosA
=2(4/5)(3/5)
=24/25
=0.96
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Answered by
1
Answer:
24/25
Step-by-step explanation:
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