find the value of sin 2A when sin A + cos A = 1
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Given,
SinA+CosA=1
Squaring on both sides,
(SinA+CosA)² = 1²
Sin²A + Cos²A +2 SinA CosA = 1
We know that Sin²A + Cos²A = 1
Placing this value in the above equation
Sin²A + Cos²A +2 SinA CosA = 1 becomes
1+2 SinA CosA = 1
2 SinA Cos A = 1-1
2 SinA Cos A = 0
Sin2A = 0 {Since, we know that Sin2A = 2 SinA CosA}
therefore, Sin2A = 0 when SinA + CosA = 1
SinA+CosA=1
Squaring on both sides,
(SinA+CosA)² = 1²
Sin²A + Cos²A +2 SinA CosA = 1
We know that Sin²A + Cos²A = 1
Placing this value in the above equation
Sin²A + Cos²A +2 SinA CosA = 1 becomes
1+2 SinA CosA = 1
2 SinA Cos A = 1-1
2 SinA Cos A = 0
Sin2A = 0 {Since, we know that Sin2A = 2 SinA CosA}
therefore, Sin2A = 0 when SinA + CosA = 1
thanx very much
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