Question

Find the value of Sin(2sin^-1 x)

Answer 1

Step-by-step explanation:

Hi Vishal

Here's your answer.

let sin^-1x=y

Sin(2y)

Sin(2y)=2sinycosy

2sin(sin^-1x)cos(sin^-1x)

[sin^-1x=π/2-cos^-1x]

2x × cos(π/2-cos^-1x)

2x × (cosπ/2-cos(cos^-1x))

2x × -x

-2x^2

Hope, it helps.

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