Math, asked by Humaira19721, 9 months ago

Find the value of sin(2tan inverse 2/3)+cos(tan inverse root 3)

Answers

Answered by Anonymous
1

Step-by-step explanation:

Sin{tan-1(4/3)/1-4/9} + Cos{Cos-1(1/2)}

Sin{tan-1(4/3)/(5/9)} + 1/2

Sin{tan-1(12/5)} + 1/2

Sin{Sin-1(12/13)} + 1/2

12/13 + 1/2

24+13/26 = 37/26

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