Question

find the value of sin 31 upon cos 59​

Answer 1

$\frac{ \sin31 }{ \cos59 } \\ = > \frac{ \sin31 }{ \cos(90 - 31) } \\ = > \frac{ \sin31 }{ \sin31 } \\ = > 1$

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Answer 2

Answer:

hey mate

Step-by-step explanation:

here is your answer

$\frac{sin31}{cos59}$

$\frac{sin \: (90 \: - \: theta)}{cos \: theta}$

$\frac{sin \: (90 \: - \: 31)}{cos \: 59}$

$\frac{sin \: 59}{cos \: 59}$

$= 1$

answer is 1

$thanku$