Find the value of Sin (-315^)
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Answered by
15
On the trig unit circle,
sin (315) = sin (-45 + 360) = sin (-45) = - sin (45)
Trig table gives -> sin315=−sin45=−√22
cos 315 = cos (- 45) = cos 45 = √22
tan315=sincos=−1
cot 315 = 1/tan = -1
sec = 1/cos = sqrt2
csc = 1/sin = - sqrt2
sin (315) = sin (-45 + 360) = sin (-45) = - sin (45)
Trig table gives -> sin315=−sin45=−√22
cos 315 = cos (- 45) = cos 45 = √22
tan315=sincos=−1
cot 315 = 1/tan = -1
sec = 1/cos = sqrt2
csc = 1/sin = - sqrt2
Naman17102000:
galat hai Sin(-315) hai sidhe 315 nahi
Answered by
20
Answer:
sin(315°)=-1/root2
Step-by-step explanation:
sin(315°)
sin(90×3+45)
90×3+45 lies in 4th quardent where sin is negetive
sin(-45)
-sin(45)
-1/root2
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