Question

Find the value of sin 32° cos 28° + cos 32° sin 28°​

Answer 1

Step-by-step explanation:

sin(a+b)==sinacosb + cosasinb

sin(32+28)=sin60=√3/2

Answer 2

sin 32° cos 28° + cos 32° sin 28° = √3/2

Given : sin 32° cos 28° + cos 32° sin 28°

To find : The value

Formula to be used :

sin ( A + B ) = sin A cos B + cos A sin B

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

sin 32° cos 28° + cos 32° sin 28°

Step 2 of 2 :

Find the value

We use the formula

sin ( A + B ) = sin A cos B + cos A sin B

Thus we get

sin 32° cos 28° + cos 32° sin 28°

= sin ( 32° + 28°)

= sin 60°

$\displaystyle \sf{ = \frac{ \sqrt{3} }{2} }$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ value of(1+tan13)(1+tan32)+(1+tan12)(1+tan33)

https://brainly.in/question/23306292

2. Find the value of p if

3cosec2A(1+COSA)(1 - COSA) =p

https://brainly.in/question/23381523