Question

find the value of sin 36 degree upon 2 cos 54 degree minus 2 sec 41 degree upon 3 cosec 49 degree​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

-1/6

Step-by-step explanation:

Prerequisites:

Sin A = Cos ( 90 - A )

Cosec A = Sec ( 90 - A )

According to the question,

Sin 40 can be written as : Cos ( 90 - 40 ) = Cos 50

And Cosec 49 can be written as Sec ( 90 - 49 ) = Sec 41

Substituting the values we get,

\implies \dfrac{Cos 50}{2\: Cos50} - \dfrac{2\:Sec41}{3\:Sec41}⟹

2Cos50

Cos50

−

3Sec41

2Sec41

Cancelling out terms we get,

\begin{gathered}\implies \dfrac{1}{2} - \dfrac{2}{3} \\\\\text{Taking LCM we get,}\\\\\implies \dfrac{3 - 4}{6} = \dfrac{-1}{6}\end{gathered}

⟹

2

1

−

3

2

Taking LCM we get,

⟹

6

3−4

=

6

−1

Hence the answer is -1/6

Thanks !!