Find the value of ( sin 45 0 - cos45 0 )
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Answered by
1
sin 45 = 1/√2
cos45 = 1/√2
So sin45 theta - cos45 theta = 1/√2 - 1/√2 = 0
HOPE THIS HELPS YOU.........
:)
cos45 = 1/√2
So sin45 theta - cos45 theta = 1/√2 - 1/√2 = 0
HOPE THIS HELPS YOU.........
:)
Answered by
0
sin 45°=1/√2
cos 45°=1/√2
∴(sin 45°-cos 45°)=(1/√2-1/√2)
(sin 45°-cos 45°)=0
cos 45°=1/√2
∴(sin 45°-cos 45°)=(1/√2-1/√2)
(sin 45°-cos 45°)=0
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