find the value of sin(45+A)-cos(45-A)
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Answered by
32
Heya,
Given;
=>sin(45° + A) - cos(45° - A)
=> sin(45° + A) - sin[90° - (45° - A)]
=> sin(45° + A) - sin(90° - 45° + A)
=> sin(45° + A) - sin(45° + A)
=> 0. ..... Answer
Hope this helps....:)
Given;
=>sin(45° + A) - cos(45° - A)
=> sin(45° + A) - sin[90° - (45° - A)]
=> sin(45° + A) - sin(90° - 45° + A)
=> sin(45° + A) - sin(45° + A)
=> 0. ..... Answer
Hope this helps....:)
himanshu1433:
thanks
wlc dear..
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Answered by
11
Hey
--> sin X = cos ( 90 - X )
-> cos ( 45 - A ) = sin ( 90 - ( 45 - A ) )
= sin ( 45 + A ) --> ( i )
Now, the question -->
---> sin ( 45 + A ) - cos ( 45 - A )
= sin ( 45 + A ) - sin ( 45 + A ) [ From ( i ) ]
= 0
Hence, the desired value is 0
--> sin X = cos ( 90 - X )
-> cos ( 45 - A ) = sin ( 90 - ( 45 - A ) )
= sin ( 45 + A ) --> ( i )
Now, the question -->
---> sin ( 45 + A ) - cos ( 45 - A )
= sin ( 45 + A ) - sin ( 45 + A ) [ From ( i ) ]
= 0
Hence, the desired value is 0
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