Find the value of
Sin(45-alpha) - cos (45+alpha)
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Answered by
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sin(45-x) - cos(45+x)
We know,
Sin(theta) = cos(90°-theta)
So,
sin(45-x) -cos(45+x)
=>cos(90-(45-x) -cos(45+x)
=>cos(90-45+x) - cos(45+x)
=>cos(45+x)-cos(45+x)
=>0
{I have taken x in place of alpha}
So,
sin(45-alpha)-cos(45+alpha)= 0
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