Question

Find the value of sin 45 degree
geometrically.

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Answer 1

hopes it's helps uh ❗ ❗

Answer 2

Answer:

Step-by-step explanation:

I think u will understand

Let ΔABC be a right angle Δ with ∠B = 90° and ∠BAC = 45°

∴∠ACB will also be 45°

∵∠BAC = ∠ACB = 45°

∴ AB = BC

Let AB = x

Then BC = x (∵AB = BC)

By Pythagorean Theorem,

AC = √(AB² + BC²)

= √(x² + x²) (∵ AB = BC = x)

=√(2x²)

∴ AC = √2 x

Now we know that cosФ = base/hypotenuse

∴ cos∠BAC = AB/AC

or, cos45° = x/√2 x (∵ ∠BAC = 45°)

∴ cos45° = 1/√2