find the value of sin 50 degree/ cos 40 degree + cosec 40 degree/ sec 50 degree -4 cos 50 degree cosec 40 degree
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Answered by
135
Hi ,
sin 50° = sin( 90 - 40 ) = cos 50 °
Cosec 40 = Cosec ( 90 - 50 ) = sec 40°
cos 50 = cos ( 90 - 40 ) = sin 40°
sin 40 Cosec 40 = 1
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sin 50 / cos40 + Cosec 40 / sec50 - 4cos50cosec40
= cos 40 / cos 40 + sec 50/ sec 50 - 4sin 40 Cosec 40
= 1 + 1 - 4
= -2
I hope this helps you.
:)
sin 50° = sin( 90 - 40 ) = cos 50 °
Cosec 40 = Cosec ( 90 - 50 ) = sec 40°
cos 50 = cos ( 90 - 40 ) = sin 40°
sin 40 Cosec 40 = 1
-------------------------------------------
sin 50 / cos40 + Cosec 40 / sec50 - 4cos50cosec40
= cos 40 / cos 40 + sec 50/ sec 50 - 4sin 40 Cosec 40
= 1 + 1 - 4
= -2
I hope this helps you.
:)
Answered by
1
Answer:
LHS=(sin10+sin50)+(sin20+sin40)
=(2sin 30cos 20)+(2sin 30cos 10)
=2sin 30(cos10+cos20)
=2×1/2 (sin80+sin70)
=sin70+sin80=RHS
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