Question

Find the value of : sin ( 50 + theta ) - cos ( 40 - theta)

Answer 1

sin(50+theta)- cos (40-theta)

= sin(90-40+theta) - cos(40-theta)
=sin[90-(40-theta)]- cos(40-theta)
=cos(40-theta)-cos(40-theta) since sin(90-theta)=cos theta
=0

Answer 2

Here your answer goes

Step :- 1

Given ,

$sin(50+theta)- cos (40-theta)$

Sin 50° can be written as 90° - 45°

⇒ Sin (90 - 40 + theta ) - Cos ( 40 - theta )

Step :- 2

⇒ sin[90-(40-theta)]- cos(40-theta)

⇒ sin[90-(40-theta)]- cos(40-theta)

⇒ $cos(40-theta)-cos(40-theta)$

∴  sin ( 90 - theta ) = Cos theta

⇒ 0

Therefore ,  Sin ( 50 + theta ) - Cos( 40 - theta ) = 0

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